An alternative to the experiment in Q.3 to investigate whether loud music tends to increase the time it takes mice to complete a maze would involve…

0.56
Difference = mu (control) – mu (rap)
Estimate for difference: -0.650
95% CI for difference: (-2.126, 0.826)
T-Test of difference = 0 (vs not =): T-Value = -0.89 P-Value = 0.380 DF = 46
(b) Use the sample summary statistics in the output to verify the value for t in this case.
(c) What is the p-value corresponding to your alternative hypothesis?
(d) State a conclusion in the context of the data.

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